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0.25x^2+6.5x-22=0
a = 0.25; b = 6.5; c = -22;
Δ = b2-4ac
Δ = 6.52-4·0.25·(-22)
Δ = 64.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.5)-\sqrt{64.25}}{2*0.25}=\frac{-6.5-\sqrt{64.25}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.5)+\sqrt{64.25}}{2*0.25}=\frac{-6.5+\sqrt{64.25}}{0.5} $
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